Statement $\left( {p \wedge q} \right) \to \left( {p \vee q} \right)$ is
contradiction
tautology
neither tautology nor contradiction
can't say
Let $p$ and $q$ be any two logical statements and $r:p \to \left( { \sim p \vee q} \right)$. If $r$ has a truth value $F$, then the truth values of $p$ and $q$ are respectively
The Boolean expression $\left( {\left( {p \wedge q} \right) \vee \left( {p \vee \sim q} \right)} \right) \wedge \left( { \sim p \wedge \sim q} \right)$ is equivalent to
When does the current flow through the following circuit
Dual of $(x \vee y) \wedge (x \vee 1) = x \vee (x \wedge y) \vee y$ is
Let $p$ and $q$ be two Statements. Amongst the following, the Statement that is equivalent to $p \to q$ is